--------------------------------- OPTIMIZE.TXT --------------------------------- Some useful informations about how to optimize code on a 386/486/Pentium This initially was a posting on the Internet made by Michael Kunstelj. Contact at : virteam@smoke.canberra.edu.au or mick@cairo.anu.edu.au Initially it included 486 and Pentium optimizations with some "holes" (like the profiling instructions), i filled the Pentium "holes" then refined some exaplanations (uh! maybe i made 'em worse! :} ). Then added some not-so-obviuos cache optimization techniques and other infos about specific optimizations you can make on 386. Lorenzo Micheletto N.B. I added some generic examples about how a cpu works BUT they are just examples, intel cpus work in slightly different ways. N.B./2 Always check in the books for things you are not sure there may be typos here. ---------------------------------- Brief intro about how a CPU works ---------------------------------- Now a brief intro on the innards Intel CPUs. Most processors these days have within in them a system termed a "pipeline". The 486 / 586 are certainly within this category. However, most people aren't quite sure what exactly a pipeline is, here follows a complete explanation: The execution of a machine code instruction can be roughtly split in five stages: [n.b. this is a generic pipeline] 1) FETCH instruction opcode and immediate data 2) DECODE opcode and align immediata data into temporary registers 3) CALCULATE ADDRESS OF OPERANDS and load 'em into memory. (calculate the address of memory locations to access and select the register operands to use) (sometimes called DECODE 2) 4) EXECUTE instruction (loading memory operands if needed) & write results to INTERNAL registers 5) WRITEBACK memory-operand results to memory Every stage takes ONE OR MORE cpu cycles to be completed, but usually a modern cpu needs just one cpu cycle for every execution stage (excluding stages 1 and 5 that have to deal with memory/cache access and stage 4 when "complex" microcoded instructions are executed). A cpu-core ( the "real" cpu, not cache support nor the other things that are usually integrated into a modern cpu) has five "specialized" units, one for every stage of instruction execution, plus a "register file" (and ultra-fast on-chip memory where internal register values are stored) and a CONTROL UNIT. The control unit "coordinates" the action of all the other units so they can work together. Here follows an extended ascii drawing of ONE on the many ways these units can be connected (use a ms-dos text editor to see this, or convert it to the Windows line-drawing character set if you are using a Windows editor): MEMORY INPUT ("memory load" unit) ³ ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿ ÀÄÄÄÄÄÂÄ>ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿<ÄÄÄÄÄÄÄÄ>³ ³ ÚÅ¿ ³ FETCH ³ ³ ³ ÚÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÙ³À>ÀÄÄÄÄÄÄÄÄÄÄÄÄÁÄÄ¿ ³ ³ ³ (instruction pointer)³ ³ ³ ³ ³ ³ ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿<ÄÙ ³ ³ ³ ³ ³ DECODE ³<ÄÄÄÄÄÄÄÄ>³ ³ ³ ³ ÀÄÄÄÄÄÄÄÄÄÄÄÄÁÄÄ¿ ³ ³ ³ ³ ³ ³ ³ ³ ³ ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿<ÄÙ ³ CONTROL ³ ³ ÚÙ ³ ADDRESS C. ³<ÄÄÄÄÄÄÄÄ>³ ³ ³ ÚÄÄÄÄÅÄÄ>ÀÄÄÄÄÄÄÄÄÄÄÄÄÁÄÄ¿ ³ UNIT ³ ³ ³ À¿ ³ ³ ³ ÚÄÄÄÄÄÁÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÁÄ¿ ÀÄ>ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿<ÄÙ ³ ³ ³ REGISTER FILE ÃÄÄÄÄÄ>³ EXECUTE ³<ÄÄÄÄÄÄÄÄ>³ ³ ÀÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÙ<ÄÄÄÄÄÁÄÄÄÄÄÄÄÄÄÄÄÄÁÄÄ¿ ³ ³ ³ ³ ³ ÚÄÄÄÄÄÄÄÄÄÄÄÄ¿<ÄÙ ³ ³ ³ WRITEBACK ³<ÄÄÄÄÄÄÄÄ>³ ³ ÀÄÄÄÄÄÄÄÄÄÄÄÄÁÄÄ¿ ³ ³ ³ ÀÄÄÄÄÄÄÄÄÄÄÄÄÙ MEMORY OUTPUT <ÄÄÄÙ ("memory store" unit) If you look the drawing, the control unit needs to communicate with all the other units to make 'em work together. Usually the "control unit" is scattered in little units that coordinates intruction and data flow between adiacent units, but you can think at it as a single indipendent unit. The five execution units are what gives the "raw" cpu power but the control unit is what lets you fully utilize 'em. Let's suppose every unit performs one operation in one step. With a "cheap" control unit, to execute a complete machine language instruction you first enable FETCH, then you enable DECODE and so on until WRITEBACK is completed and the control unit enables FETCH again to execute the next instruction. This is what happens into an "absolutely not pipelined" cpu with "one cycle" stages, the fastest instructions takes 5 cycles but the control unit is very simple (just a circular shift register that enables one unit at a time). Of course this is the worst case, nobody is so jerk to build a cpu like that. Every cpu stage-execution unit is a stand alone thing, it has its hardware and its "temporary registers" so it is capable to operate "alone". So, IF THE CONTROL UNIT can SINCHRONIZE the operations of all the stage-execution units, it can make 'em WORK IN PIPELINE (like in a factory, where every worker/robot in a production line a) receives a partially refined product from the previous worker in line b) performs some simple operations to refine the product a little more c) pass the result to the next worker in line ). A cpu with such a control unit is called a pipelined CPU. If you have to execute in sequence instructions A,B,C,D,E on a pipelined processor .... While the WRITEBACK unit is performing stage 5 of A the EXECUTION unit can perform stage 4 of B the ADDRESS CALCULATE unit can perform stage 3 of C the DECODE unit can perform stage 2 of D and the FETCH unit can perform stage 1 of E So if you start the cpu at instruction A it looks like that instruction A takes 5 cycles while instructions B,C,D,E (immediately one stage behind) looks like they take JUST ONE CYCLE!!! So if you execute a SEQUENCE of 8 instructions on a "not pipelined" processor with a five stage "pipe" it takes 40 steps to execute the sequence while on a pipelined processor this takes 5+7=12 steps!!! ( 5 steps for the first instruction to get thru the pipeline then 7 steps for the other instructions immediately "one step" behind) And the more instructions are executed in sequence, the more it looks like every instruction takes "just" one cycle to execute. This is of course the optimal situation, when the processor pipeline is filled and WHEN EVERY INSTRUCTION DOES NOT USE MEMORY/REGISTER OPERANDS "still under processing" IN SUCCESSIVE EXECUTION-STAGES!!!!!! ------------------------------------------------------------------------------- THINGS A CPU MUST CHECK TO MAKE A PIPELINE WORK CORRECTLY A pipelined processor control-unit must "check" : A) at stage 1 (FETCH) IF in stage 2..4 there are JUMP instructions [ they change the program counter (the same register used by the fetch unit) ] THEN stage 1 must "wait" until the jump is completed and then "restarts", loading the memory location pointed by the new program counter value. Because the jump opcode must pass thru the decode stage ... ... if the DECODE unit "detects" a jump opcode, it makes the FETCH unit "stops" AT LEAST for two cycles until the jump is performed. This of course means the processor pipeline "wastes" some cpu cycles. A 486 handles jumps in a smarter way, when the FETCH unit loads a jump instruction, it goes on assuming the jump WON'T BE TAKEN (it read the instructions following the jump). If the jump is taken, the values in the DECODE 1 and DECODE 2 units are "discarded" and the FETCH unit starts loading from the new program counter value. This explains why on 486 relative jumps (the fastest jumps) takes 3 cycles if taken (two cycles "lost") 1 cycle if not taken (no cycles lost) A "smarter" control unit can recognize in advance unconditional jumps and start immediately loading opcodes from the new program counter location AND/OR try to "predict" the jump destination of conditional jumps (like the Pentium does). B) at step 3 (ADDRESS CALCULATION) IF in stage 3 a register needed for address calculation is under processing in stage 4 (EXECUTE) THEN the stage 3 unit generates a "do nothing" control sequence for one cpu cycle. C) memory access conflicts These can be caused by lots of different things, they are usually resolved by the memory load/store units. Told in a short way, in a fully pipelined processor when the pipeline is "working on a sequence" the first instruction in the sequence takes the full execution time while the other instructions takes a shorter time (usually one cycle) because they are immediately behind, this means they "look faster" (and in fact they are, because the pipeline fully utilizes all the functional units it has). If some instructions "modify" values needed in the previous cpu stages the control unit stops the unit needing those values (and the others behind it) and inserts "do nothing" codes into the successive units in the processor pipe to make things work as expected (this is called a PIPELINE STALL or a PIPELINE FLUSH) This explains why usually a taken jump takes more time than one that's not taken (when a jump is performed you must flush the pipeline). The newer processors includes JUMP PREDICTION UNITS that handles jump faster, but the less you jump, the better. ------------------------------------------------------------------------------ PIPELINING IN INTEL PROCESSORS: The 386 is a "partially pipelined" processor with some optimizations. It checks for jumps ( A check) in a quite slow way and most of times can execute every stage in one cycle. It cannot perform the address generation check (B check) so it must execute stage 3 and 4 in "not pipelined mode". This explains why THE FASTEST 386 INSTRUCTIONS TAKE TWO CYCLES ( stage 3 unit must wait stage 4 to complete before managing the next instructions). The 486 has an improved EXECUTION unit (stage 4), improved memory access AND its control unit can perform the address generation check so that it can pipe stage 3 and 4 if there are no register/memory conflicts with two successive instructions. This explains why lots of 486 instructions take just one cycle (if the pipeline is filled and no pipeline stalls are produced). What's more, pipeline reloading is improved, so even jumps have less impact on execution time. It also has a 4Kbyte internal cache that boosts memory access and allows big gains from strip-mining optimizations. Another nice thing is the BURST READ access that accelerates memory reads when it needs to update its internal cache. PIPELINED,SUPERSCALAR & BRANCH PREDITING CPU: THE PENTIUM Well, what's beyound a fully pipelined processor like the 486 ? There is a 586/Pentium processor, that's SUPER SCALAR (more than one pipeline) and BRANCH PREDICTING (it has a specialized unit that annotates the position and the result of some og the most recent jumps, and so it can try to "guess" from where the next instruction after the jump execution will be loaded, if it guess correcly a pipeline stall is avoided, else it stalls)(this helps speeding up the execution of nested loops). The 586 can execute UP TO TWO integer operations in a single step (because it has TWO pipelines, but with some limitations) it can BURST READ/WRITE and has TWO indipendent 8k caches (Harvard style CPU to cache architecture) this means you can strip-mine to the max. if strips fit into the 8Kbyte data cache. Well, now you know how they work, let's see how to make 'em work to the max. ------------------------------------------------------------------------------ SPEEDING UP 486/586 CODE. ------------------------------------------------------------------------------ ------------------------------- ADDRESS GENERATION STALLS (AGI) ------------------------------- An Address Generation Interlock occurs when a register which is currently being used as the base or an index was the destination component of a previous instruction (the stage 3 to 4 pipeline stall i described above) For example,: add edx, 4 // AGI, ONE CLOCK STALL mov esi, [edx] For the 486, AGI's can only occur on adjacent instructions. On the 586 or Pentium instructions up to 3 locations away can cause an AGI. ( i.e. an instruction waiting to execute step 4 on pipeline 1 may need to wait the result produced by an instruction still executing on pipeline 2) pipeline step pipe1 pipe2 addres_calculate/fetch_operand C D | execute B A | V If C needs the results of A, it must stall pipeline 1 for one cycle to wait for A to "exit from" pipeline 2. If C needs the results of D, it must stall pipeline 1 for two cycles to wait for D to "exit from" pipeline 2. An example of 3 instruction away AGI: add esi, 4 pop ebx dec ebx mov edx, [esi] Takes 4 clocks on a 486. On a 586, the move command must wait for the add command, thus AGI stalling for one clock. The code above then would run in three clock cycles on a 586. Remember that even instructions that read or write implicitly to registers cause AGI stalls: mov esp,ebp pop ebp. is executed as... mov esp,ebp [agi] ; pop uses the esp as a pointer pop ebp ---------------------------- INSTRUCTION DECODING STALLS: ---------------------------- When decoding an instruction with an IMMEDIATE VALUE AND either an INDEX OFFSET or an IMMEDIATE DISPLACEMENT 486's have a one clock penalty. (586's do not) Example: mov spam, 248 mov dword ptr [esp+4], 1 This happens because the decode stage of the pipeline can read and decode ONE "immediate" value at a time while an immediate value and an immediate offset are TWO immediate values. The 586 instead has not such problems (when decoding) (execution is different) --------------------------------- REGISTER ACCESS CPU STALLS: --------------------------------- 486's have a 1 clock penalty when modifying the lower word of a DWORD register that's used immediately after it, 586's do not. Example: mov al,0 mov [ebp], eax (a one clock penalty on 486, no penalty on a 586) ------------------------------- CODE ALIGNMENT ------------------------------- To speed up the instructions, alignment of code should be on the beginning of cache boundaries. (32 bytes on 586, 16 bytes on 486) Thus, start your routine on the start of the cache page. This way, when someone calls the routine, the processor will just have to load a cache line to get the first sequence to feed into the pipeline, and while they are executing it will have enough time to load the other cache lines needed. This will speed up the processing of all the instructions within that page. The effect of this speed up on the 586 is not a dramatic as is it is on the 486 because the 586 has bigger caches and faster access to memory so a cache line load/store has less impact on cpu. ------------------------------ DATA ALIGNMENT ------------------------------ Misaligned access in the data cache causes an extra 3 cycles on both the 486 and 586. Ways to speed up data: For DWORD data, alignment should be on a 4-byte boundary. For WORD data, alignment should be on a 2 byte boundary for the 486, and simply within the 4-byte page for the 586. For 8 byte data (64 bits), data should be aligned on a 8-byte boundary so it is possible to use BURST READS (and burst writes too, on a Pentium). And yes, on many applications with tight inner loops, these things do accumulate to make a noticeable speed-up. ------------------------------------------------------------------------------- SPEEDING UP REGISTER AND OPERAND USAGE ------------------------------------------------------------------------------- Use the EAX as much as possible. Many instructions are 1 byte shorter when using EAX. That's less code you have to move around and slightly less internal processing. Use the DS register as much as possible for roughly the same reason, In the case of several references being made to a variable addressed with a displacement, load the displacement into a register. Try to use the ESP register to reference the stack in lower levels of your subroutines (faster than push/pop things and leaves EBP free for other uses) ------------------------------------------------------------------------------- HANDY INFO ON SPEEDING UP INTEGER INSTRUCTIONS ------------------------------------------------------------------------------- 1. Avoid using complex instructions like LEAVE, ENTER, LOOP, string instructions etc Simpler instructions will get the job done faster. Simpler instructions have been getting faster with every new processor that has come along. 2. With 8-bit operands, do your best to use the byte opcodes, rather than using the 32 bit instructions with sign and zero extended modes. Internal sign extension is expensive, and speed increases can be found by simplifying the process as much as possible. 3. LEA's generally increase the chance of AGI's. However, LEA's can be advantageous because: * In many cases an LEA instruction may be used to replace constant multiply instructions. (a sequence of LEA, add and shift for example) * LEA may be used as a three/four operand addition instruction. LEA ECX, [EAX+EBX*4+ARRAY_NAME] * Can be advantageous to avoid copying a register when both operands to an ADD are being used after the ADD as LEA need not overwrite its operands. The general rule is that the "generic" LEA A,[B+C*INDEX+DISPLACEMENT] where A can be a register or a memory location and B,C are registers and INDEX=1,2,4,8 and DISPLACEMENT = 0 ... 4*1024*1024*1024 or (if performing signed int operations) -2*1024*1024*1024 ... + (2*1024*1024*1024 -1 ) replaces the "generic" worst-case sequence MOV X,C ; X is a "dummy" register MOV A,B MUL X,INDEX ;actually SHL X, (log2(INDEX)) ADD A,DISPLACEMENT ADD A,X So using LEA you can actually "pack" up to FIVE instructions into one Even counting a "worst case" of TWO OR THREE AGIs caused by the LEA this is very fast compared to "normal" code. What's more, cpu registers are precious, and using LEA you don't need a dummy "X" register to preserve the value of B and C. 4. Zero-Extension with short ints terror tales The MOVZX takes four cycles to execute due to due zero-extension wobblies. A better way to load a byte into a register is by: xor eax,eax mov al,memory As the xor just clears the top parts of EAX, the xor may be placed on the OUTSIDE of a loop that uses just byte values. The 586 shows greater response to such actions. It is recommended that 16 bit data be accessed with the MOVSX and MOVZX if you cannot place the XOR on the outside of the loop. N.B. Do the "replacement" only for movsx/zx inside loops. 5. When comparing a value in a register with 0, use the TEST command. TEST operands by ANDing the operands together without spending any internal time worrying about a destination register. Use test when comparing the result of a boolean AND command with an immediate constant for equality or inequality if the register is EAX. You can also use it for zero testing. (i.e. test ebx,ebx sets the zero flag if ebx is zero) 6. Address Calculations Pull address calculations into load and store instructions. Memory reference instructions have 4 operands: a relocatable time segment base, a base register, a scaled index register and a displacement. Often several integer instructions can be eliminated by fully using the operands of memory addresses. (more on this later) 7. INTEGER DIVIDE In most cases, an Integer Divide is preceded by a CDQ instruction. This is as divide instructions use EDX:EAX as the dividend and CDQ sets up EDX. It is better to copy EAX into EDX, then arithmetic-right-shift EDX 31 places to sign extend. The copy/shift instructions take the same number of clocks as CDQ, however, on 586's allows two other instructions to execute at the same time. If you know the value is a positive, use XOR EDX,EDX. 8. INTEGER MULTIPLY The integer multiply by an immediate can usually be replaced with a faster and simpler series of shifts, subs, adds and lea's. As a rule of thumb when 6 or fewer bits are set in the binary representation of the constant, it is better to look at other ways of multiplying and not use INTEGER MULTIPLY. (the thumb value is 8 on a 586) A simple way to do it is to shift and add for each bit set, or use LEA. Here the LEA instruction comes in as major cpu booster, for example: LEA ECX,[EDX*2] ; multiply EDX by 2 and store result into ECX LEA ECX,[EDX+EDX*2] ; multiply EDX by 3 and store result into ECX LEA ECX,[EDX*4] ; multiply EDX by 4 and store result into ECX LEA ECX,[EDX+EDX*4] ; multiply EDX by 5 and store result into ECX LEA ECX,[EDX*8] ; multiply EDX by 8 and store result into ECX LEA ECX,[EDX+EDX*9] ; multiply EDX by 9 and store result into ECX And you can combine leas too!!!! lea ecx,[edx+edx*2] ; lea ecx,[ecx+ecx*8] ; ecx <-- edx*27 (of course, if you can, put three instructions between the two LEA so even on Pentiums, no AGIs will be produced). 9. Clearing Registers Using XOR reg,reg is fast but sets up conditions codes. A slightly slower way to do it of course is to mov reg,0 which preserves condition codes. 10. Avoid ENTER, instead, try something like: PUSH EBP mov ebp, esp sub esp, BYTE_COUNT 11. JUMP INSTRUCTIONS Jump instruction come in two forms, one real near that jumps between -127 and 128 of the current location, and a 32 bit version that does a full jump. The short form is quite a bit faster, however unfortunately many compilers put long jumps where short jumps would suffice. To ensure that short jumps can be used (when you know it is possible), explicitly specify the destination as being byte length (i.e use jmp short instead of plain jmp, if you can) 12. Task Switching Task Switching is evil. It is slow, real slow. Avoid task switching too often, as more and more of your time will be spent in processing the task switch. For faster task switching, perform you task switching in software. This allows a smaller processor state to be saved and restored. Anything that shaves time off 75+ clock cycles isn't all that bad in my book. 13. Minimize segment register loads and the use of far pointers as dearly much as you can. If you are doing a lot of processing on a small piece of data far away, it might be faster just to copy the data to nearby and work on it there (by the way, this is a good reason to use flat protected mode). ...and.... 14. THINK ABOUT WHAT YOU WANT TO DO All the other optimisations of Unrolling Loops, moving the invariant data etc still apply. That, however, is more an algorithmic problem for you, but still keep it firmly in mind. _______________________________________________________________________________ 586 Specific Optimizations ------------------------------------------------------------------------------- The 586Pent has a five stage pipeline structure. However, the pipeline is split into two different pipelines, known as Pipeline U and Pipeline V. This allows two instructions to be executed in parallel and thus presents the opportunity of executing two/instuctions per clock. The U pipeline is very much like the 486 pipeline, in that it can handle the entire set of instructions. Pipeline V on the other hand can handle only "simple" instructions. The fast parts of the U and V pipelines are possible as much of the functions are hardwired not microcoded. Anyway, I've blurted on about that for a bit, but what you want to know is "How to I get two instructions running in one clock/cycle?" Lament no further, here are the criteria: 1. Both instructions must be simple (see below) 2. There must not be a read-after-write or write-after-read register/flag dependencies between them. 3. Neither can have a displacement and an immediate 4. Instructions with prefixes can only occurr in the U-pipe (except for branches on condition jz,jc, etc.etc.) The following are considered "simple" instructions, the ALU means any ALU command (ADD etc): 1. Mov reg, reg/mem/immed 2. mov mem, reg/imm 3. ALU reg, reg/mem/immed 4. ALU mem, reg/immed 5. inc reg/mem 6. dec reg/mem 7. push reg/mem 8. pop reg 9. nop 10. lea reg/mem 11. Jmp/ Call / Jcc near N.B Remember only the U pipe can perform SHIFTS/ROTATIONS so "couple" every shift/rol with a simple instruction before and after to be sure every pipeline is filled. Note, however, than while both pipelines can perform ALU instructions concurrently, this is not the case when one ALU instruction requires the output of the other pipeline ALU instruction. Example: ALU instruction in pipe U and performing ADC in pipe V. There are two exceptions to this rule: 1) In the case of a compare/branch combination. 2) With push/pop combinations (because of optimized stack access) -------------------------- Branch Prediction ------------------------- Another nice optimisation with the 586 hardware is that whenever there is a possibility of a jump, for example, Jg, the 586 can automatically start "reading ahead" code from the jump location just in case the the Jump is accepted. Remember the CODE alignment thing above? Well, it couldn't hurt your grandmother to align the labels on the code pages. ------------------------------------------ Amazing new 586 Optimizations and speedups ------------------------------------------ The 586 has a lot of really nice optimizations and kick-ass features in addition to what I've mentioned above, unfortunately, this information is proprietary and will only be given to people who sign non-disclosure agreements and shell out a $$ or two... Bummer... (Meethinks, 586 clone-makers won't be too happy about that... :-) ) Compiler/OS makers will probably be the purchasers. Quite a few of these optimisations won't work on anything less than a 586, so don't sweat too much about it. Hey, just write for 386/486/586 and you'll be ok. Hovewer, i found a nice article on July 1994 Byte about some "secret weapons of Pentium coders".... ============================================================================ PENTIUM'S PROFILING REGISTERS: Pentiums have a set of 64bit "machine specific registers" (MSR) that are accessed by way of the RDMSR (read MSR) and WRMSR (write MSR) instructions. THESE ARE PROTECTED MODE, RING 0 INSTRUCTIONS (CPU LEVEL 0) ( can work in a 386Powered programs only if executing under VCPI XMS or "no V86 manager" or if you find a way to "toggle" DPMI from ring 3 to ring 0) (I think they can work even if you boot ms-dos in real mode and use the proper instruction prefixes needed to execute 32bit instructions in real mode). ----------------------------------------------------------- RDMSR Read MSR Copies the MSR register indexed by ECX into the 64bit pair EDX:EAX RDMSR macro db 0Fh,032h endm ----------------------------------------------------------- WRMSR Write MSR Copies into the MSR register indexed by ECX the value contained into the 64bit pair EDX:EAX Macro to insert it into code if your assembler does not support Pentiums: WRMSR macro db 0Fh,030h endm ----------------------------------------------------------- Intel Pentium user manuals, documents only MSR 0, 1 and 0Eh and states that MSR 3, 0Fh and above 13h are reserved and illegal. So, what's left? And what's useful to you ? MSR 10h is the counter of CPU CYCLES since last power-up. That value can also be read with the RDTSC (Read time stamp counter) instruction) RDTSC is 0Fh,031h in bytes and must be executed while in ring 0 too. MSR 10h is the most precise timer available on the Pentium because it "ticks" at the CPU frequency. Then comes MSR 11h,12h and 13h there you will find the hot stuff The lower 32bits of MSR 11h are actually two INDEXES INTO THE CPU PROFILING REGISTERS!!!! The profiling registers are CPU EVENT TIMERS AND COUNTERS they can keep track of what's going on inside and outside your super-duper processor, they can detect nearly everything the CPU does. The first 16bits of MSR11h selects the profiling register accessible thru MSR 12h. The second 16bits of MSR11h selects the profiling register accessible thru MSR 13h. Here comes the format of the "profiling register indexes": bit 0..5 : type of the profiling register to access bit 6 : Set if you want to monitor the events in cpu ring 0,1,2 (system) bit 7 : Set if you want to monitor the events in cpu ring 3 (user level) bit 8 : 0 = access count-of-hardware-events 1 = access count-of-total-cpu-cycles used to process the cumulated events. (i'm not sure of this, maybe 0 means count time and 1 count events) bit 9..15: UNKNOWN, DO NOT MODIFY Profiling registers types: INDEX NAME 0 data write 1 data read 2 data TLB miss (translation look-aside buffer) 3 data read miss 4 data write miss 5 write (hit) to M or E state lines 6 data cache lines written back 7 data cache snoops 8 data cache snoop hits 9 memory accesses in both pipes 0Ah bank conflict 0Bh misaligned data memory reference 0Ch code read 0Dh code TLB miss 0Eh code cache miss 0Fh segment load 10h ???? 11h ???? 12h branches 13h BTB hits (Branch Target Buffer) 14h taken branch OR BTB hit 15h pipeline flushes 16h instructions executed 17h instructions executed in V-pipe 18h bus utilization (clocks) 19h pipeline stalled by write backup 1Ah pipeline stalled by data memory write 1Bh pipeline stalled by write to E or M line 1Ch locked bus cycles 1Dh i/o read or write cycles 1Eh non cacheable memory references 1Fh AGI (Address Generation Interlock) 20h ???? 21h ???? 22h FPU operations 23h breakpoint 0 match 24h breakpoint 1 match 25h breakpoint 2 match 26h breakpoint 3 match 27h hardware interrupts 28h data read or data write 29h data read miss or data write miss So if you want to profile things: 0) Set properly the environment of the test (cache empty, cache filled with all the routine code, etc. etc.) 1) Set MSR 11h to the two counters you want to read 2) Read MSR 12h,13h to get the initial values, 3) Execute the code you want to profile 4) Read the final values of MSR 12h,13h (without setting MSR 11h again this time). 5) Calculate the difference between the initial and final values. This way if you are not sure how to optimize things you can actually test how they work and what's going on. USING THE PROFILING REGISTER YOU CAN "TEST ON THE ROAD" YOUR CODE DOWN TO THE LAST CPU CYCLE!!!!! ------------------------------------------------------------------------------- 386 Optimization ------------------------------------------------------------------------------- Well, nobody buys a 386 now, right? But still lots of people has one.... So if you wanna be 386 friendly remember ..... -------------------------- DECODE-AFTER-JUMP OVERHEAD -------------------------- When a jump is performed, a 386 spends some extra time decoding the next instruction to execute and flushing the pipeline. THE FIRST INSTRUCTION requires exactly ONE EXTRA CPU CYCLE for every COMPONENT ( prefixes, opcode, mod/rm , sib ,offset, immediate value ) of the instruction. Notice i said COMPONENT!!! An 8bit displacement or a 32bit one, count always as an 1 extra cycle. So, in 32bit mode (where no prefixes are needed for 32bit instructions): loopme: inc esi ; opcode mov [edi+1234h],eax ; opcode, mod/rm , immediate offset dec ecx ; opcode jne short loopme ; opcode short_displacement IS FASTER THAN: loopme: mov [edi+1234h],eax inc esi dec ecx jne short loopme Because placing first the three component mov instruction adds 2 cycles to the instruction execution time, weird, uh? But if you remember this thing, you can boost 386 code a lot. By the way, remember that "pipeline overhead" is not so obvious to calculate. Look at this: add eax,ebx ; opcode, mod/rm add eax,1234h ; opcode, immediate_value stosd ; opcode <--- these "slow" instruction pipes-in faster pop eax ; opcode <--- so if you can, put 'em first ------------------ SHORT INSTRUCTIONS ------------------ Short instructions are loaded and decoded faster than longer ones and since 386 has no internal cache and less memory access bandwidth than a plain 486, this helps a lot. Well that's all for a 386. ------------------------------------------------------------------------------- CACHE OPTIMIZATION TECHNIQUES (THEY CAN WORK ON ANY CPU!!!!!!!!!!!!) ------------------------------------------------------------------------------- Usually "code optimization" is cpu-based, but there more things up in the sky and down on earth than just a cpu... the cache for example! Well, the difference between a cache hit and a cache miss means lots of cpu cycles lost, so better hit the cached locations to the max. 386 usually have and external 64k ... 128k cache (mine has none, sigh! :( ) 486 have a 4k internal cache and a 64k...512k (usually 256k) second level cache Pentiums have an Harvard 8k code + 8k data cache plus a 256k..1Mbyte second level cache. Use "short" loops so there is more probability that the code to execute will reside fully into the cache. Then remember you can count on an external cache of at least 64k (usually 128k..256k for a 486). So, if you have to process big arrays or big bitmaps with multiple passages do not "scan" all the array for every pass, use a "strip by strip" strategy instead so every "strip" fully fits into the cache and is ready for the second and third pass without cache misses. This technique is called STRIP-MINING, you can include into your program a routine that checks the optimal "strip size" trying a multi-pass test on 64k,128k,256k,512k strips and "complete array" and then sets the optimal "strip size" to use when perfoming "strip-mining" routines. On a Pentium you can use 8k "strips" so your "strip mined" routines will work with the full speed of the internal data cache (remember the internal cache works at full cpu speed while the secondary cache may be runnin at half that). The advantage of strip mining is caused by the fact that the additional jumping/looping needed to process arrays in "strips" of adiacent memory locations that can fit together into the cache is A LOT LESS than the time caused by a single cache miss. ------------------------------------------------------------------------------- NOT SO OBVIOUS OPTIMIZATIONS ------------------------------------------------------------------------------- ---------------------- COMPLEX INSTRUCTIONS ---------------------- Intel says complex instruction are evil on 486 and up, but there are exceptions... expecially if want to make things run smooth on 386 too. STRING instructions are FASTER on 386, expecially if they are the first in a loop. If you have to move data in 32bit chunks you'd better use REP MOVSD if you can because it alone replaces this "simple instructions only" super-optimized sequence: rep_loop: mov eax,[esi] add esi,4 ; or -4 mov [edi],eax add edi,4 ; or -4 dec ecx jne rep_loop REP MOVSD takes 2+7*n cycles on a 386 or 486 While the "optimized" sequence uses EAX and takes [(2+4+2+2+2+2+7)*n - 4 ] = [21*n - 4] cycles on a 386 and [ (1+1+1+1+1+3)*n - 2 ] = [ 8*n - 2] cycles on a 486 Cache-line aligning the "optimized" code on a Pentium i think it takes [ 3*n ] cycles. So if 486s are your base system don't throw away REP MOVSD Also remember that REP MOVSD take 2 bytes instead of 13 bytes does not need to use EAX (one more register free for other things) and it does not use the Pentium's BTB (Branch Target Buffer) so you can be sure it does not miss and the outer loops with entries in the BTB can be one level deeper. What's more, the AMD K5 automatically splits a complex instruction into an optimized sequence of simple instructions and issues them to fully utilize the four execution units it has. Guess what it means for poor old movsd :) Discuss this article in the forums
See Also: © 1999-2011 Gamedev.net. All rights reserved. Terms of Use Privacy Policy
|